15th term of A.P., x – 7, x – 2, x + 3, …….. is
A. x + 63 B. x + 73 C. x + 83 D. x + 53 Answer: Option AShow Answer
Solution(By Apex Team)
$\begin{array}{l}a_n=a+(n-1)\times d\\
\text{ where, }\\
d=x-2-x+7=5\\
a=x-7\\
\Rightarrow a_{15}=(x-7)+(15-1)\times5\\
\Rightarrow a_{15}=(x-7)+14\times5\\
\Rightarrow a_{15}=x-7+70\\
\Rightarrow a_{15}=x+63\end{array}$
Related Questions On Progressions
How many terms are there in 20, 25, 30 . . . . . . 140?
A. 22B. 25
C. 23
D. 24
Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.
A. 5B. 6
C. 4
D. 3
Find the 15th term of the sequence 20, 15, 10 . . .
A. -45B. -55
C. -50
D. 0
The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is
A. 600B. 765
C. 640
D. 680