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15th term of A.P., x – 7, x – 2, x + 3, …….. is

A. x + 63 B. x + 73 C. x + 83 D. x + 53 Answer: Option A
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Solution(By Apex Team)

$\begin{array}{l}a_n=a+(n-1)\times d\\ \text{ where, }\\ d=x-2-x+7=5\\ a=x-7\\ \Rightarrow a_{15}=(x-7)+(15-1)\times5\\ \Rightarrow a_{15}=(x-7)+14\times5\\ \Rightarrow a_{15}=x-7+70\\ \Rightarrow a_{15}=x+63\end{array}$

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