### 60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is –

A. 44 kg B. 53 kg C. 80 kg D. 24 kg Answer: Option A

### Solution(By Apex Team)

\begin{aligned}&\text{Quantity of tin in 60 kg of A}\\ &=\left(60\times\frac{2}{5}\right)\mathrm{kg}\\ &=24\mathrm{~kg}\\ &\text{Quantity of tin in 100 kg of B}\\ &=\left(100 \times \frac{1}{5}\right) \mathrm{kg} \\ &=20 \mathrm{~kg}\end{aligned} ∴ Quantity of tin in the new alloy = (24 + 20) kg = 44 kg

## Related Questions On Alligation

A. 2 : 5
B. 3 : 5
C. 5 : 3
D. 5 : 2

### An alloy contains zinc, copper and tin in the ratio 2 : 3 : 1 and another contains copper, tin and lead in the ratio 5 : 4 : 3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:

A. $\large\frac{1}{2} \mathrm{~kg}$
B. $\large\frac{1}{8} \mathrm{~kg}$
C. $\large\frac{3}{14} \mathrm{~kg}$
D. $\large\frac{7}{9} \mathrm{~kg}$

A. 81 litres
B. 71 litres
C. 56 litres
D. 50 litres