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60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is –

A. 44 kg B. 53 kg C. 80 kg D. 24 kg Answer: Option A
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Solution(By Apex Team)

$\begin{aligned}&\text{Quantity of tin in 60 kg of A}\\ &=\left(60\times\frac{2}{5}\right)\mathrm{kg}\\ &=24\mathrm{~kg}\\ &\text{Quantity of tin in 100 kg of B}\\ &=\left(100 \times \frac{1}{5}\right) \mathrm{kg} \\ &=20 \mathrm{~kg}\end{aligned}$ ∴ Quantity of tin in the new alloy = (24 + 20) kg = 44 kg

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