a, b, c, d, e, f, g are consecutive even numbers. j, k, l, m, n are consecutive odd numbers. The average of all the numbers is :

A. $3\left(\large\frac{a+n}{2}\right)$

B. $\left(\Large\frac{1+d}{2}\right)$

C. $\left(\Large\frac{a+b+m+n}{4}\right)$

D. $3\left(\Large\frac{j+c+n+g}{4}\right)$

Show Answer


Solution(By Apex Team)

$\begin{array}{l}\text{According to the question,}\\ \text{Consecutive even numbers}\\ \text{= a, b, c, d, e, f, g}\\ \text{Consecutive odd numbers}\\ \text{= j, k, l, m, n}\\ \text{Consecutive even numbers}\\ \text{2, 4, 6, 8, 10, 12, 14}\end{array}$ $\begin{array}{l}\Large\frac{2+4+6+8+10+12+14}{7}\\ =\Large\frac{56}{7}\\ =8\text{ middle term}\\ \text{Consecutive odd numbers}\\ 1,3,5,7,9\\ \Large\frac{1+3+5+7+9}{2}\\ =\Large\frac{25}{5}\\ =5\text{ middle term }\end{array}$ ∴ Same as in above situation. Average of even numbers = d Average of odd numbers = 1 ∴ Average of all numbers $=\left(\Large\frac{1+d}{2}\right)$

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    Objective Test:-


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