### A cricketer whose bowling average is 24.85 runs per wickets, takes 5 wickets for 52 runs in next inning and thereby decreases his average by 0.85. The number of wickets taken by him till the last match was :

A. 75 B. 85 C. 80 D. 96 Answer: Option B
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### Solution(By Apex Team)

$\begin{array}{l}\text{Let the number of wickets = x}\\ \text{According to question,}\\ \begin{array}{l} \Rightarrow 24.85 x+52=24(x+5) \\ \Rightarrow 24.85 x+52=24 x+120 \\ \Rightarrow 0.85 x=68 \\ \Rightarrow x=\large\frac{69 \times 100}{85} \\ \Rightarrow x=80 \end{array}\end{array}$ Number of wickets till the last match is $\begin{array}{l}\text{= x + 5}\\ \text{= 80 + 5}\\ \text{= 85}\end{array}$

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A. 10 years
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### If the arithmetic mean of 0, 5, 4, 3 is a, that of -1, 0, 1, 5, 4, 3 is b and that of 5, 4, 3 is c, then the relation between a, b, and c is.

A. a = b = c
B. a : b : c = 3 : 2 : 4
C. 4a = 5b = c
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