A lump of two metals weighing 18 g is worth Rs. 87 but if their weight is interchanged, it would be worth Rs. 78.60. If the price of one metal be Rs. 6.70 per gram, find the weight of the other metal in the mixture.
A. 8g B. 12g C. 15g D. 18g Answer: Option AShow Answer
Solution(By Apex Team)
Cost of (18g of 1st metal + 18g of 2nd metal) = Rs. 165.60
Cost of (1g of 1st metal + 1g metal of 2nd metal) = Rs. 9.20
Hence cost of 1g of 2nd metal,
= 9.20 – 6.70
= Rs. 2.5
Mean price = Rs. $\Large\frac{87}{18}$
Now, given ratio of Ram and Shayam’s weight = 4 : 5
Now,
$\begin{array}{l}\Large\frac{\text { quantity of } 1^{\text {st }} \text { metal }}{\text { quantity of } 2^{\text {nd }} \text { metal }}=\frac{14}{6}: \frac{56}{30}\\
=5 :4\end{array}$
Quantity of 2nd metal = $\Large\frac{18 \times 4}{9}$ = 8 g
Now, given ratio of Ram and Shayam’s weight = 4 : 5
Now,
$\begin{array}{l}\Large\frac{\text { quantity of } 1^{\text {st }} \text { metal }}{\text { quantity of } 2^{\text {nd }} \text { metal }}=\frac{14}{6}: \frac{56}{30}\\
=5 :4\end{array}$
Quantity of 2nd metal = $\Large\frac{18 \times 4}{9}$ = 8 g
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