A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

A. 4 litres, 8 litres B. 6 litres, 6 litres C. 5 litres, 7 litres D. 7 litres, 5 litres Answer: Option B

Solution(By Apex Team)

Let the cost of 1 litre milk be Rs. 1 Milk in 1 litre mixture in 1st can = $\Large\frac{3}{4}$ litre, C.P. of 1 litre mixture in 1st can Rs.$\Large\frac{3}{4}$ Milk in 1 litre mixture in 2nd can = $\Large\frac{1}{2}$ litre, C.P. of 1 litre mixture in 2nd can Rs.$\Large\frac{1}{2}$ Milk in 1 litre of final mixture = $\Large\frac{5}{8}$ litre, Mean price = Rs.$\Large\frac{5}{8}$ By the rule of alligation, we have: ∴ Ratio of two mixtures = $\Large\frac{1}{8}: \frac{1}{8}$ = 1 : 1 So, quantity of mixture taken from each can = $\left(\large\frac{1}{2} \times 12\right)$ = 6 litres

Related Questions On Alligation

A. 2 : 5
B. 3 : 5
C. 5 : 3
D. 5 : 2

An alloy contains zinc, copper and tin in the ratio 2 : 3 : 1 and another contains copper, tin and lead in the ratio 5 : 4 : 3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:

A. $\large\frac{1}{2} \mathrm{~kg}$
B. $\large\frac{1}{8} \mathrm{~kg}$
C. $\large\frac{3}{14} \mathrm{~kg}$
D. $\large\frac{7}{9} \mathrm{~kg}$

A. 81 litres
B. 71 litres
C. 56 litres
D. 50 litres

A. 1 : 2
B. 1 : 3
C. 2 : 1
D. 3 : 1