### A student obtained 60, 75 and 85 marks respectively in three monthly examinations in Physics and 95 marks in the final examination. The three monthly examinations are equal weighted whereas the final examination is weighted twice as much as a monthly examination. His average marks in physics are-

A. 78.75 B. 79 C. 82 D. 85 Answer: Option C

### Solution(By Apex Team)

\begin{aligned}&\text{ Average marks in Physics }\\ &=\frac{60\times1+75\times1+85\times1+95\times2}{1+1+1+2}\\ &=\frac{60+75+85+190}{5}\\ &=\frac{410}{5}\\ &=82\end{aligned}

## Related Questions On Average

A. 20
B. 21
C. 28
D. 32

A. 18
B. 20
C. 24
D. 30

A. 10 years
B. 10.5 years
C. 11 years
D. 12 years

### If the arithmetic mean of 0, 5, 4, 3 is a, that of -1, 0, 1, 5, 4, 3 is b and that of 5, 4, 3 is c, then the relation between a, b, and c is.

A. a = b = c
B. a : b : c = 3 : 2 : 4
C. 4a = 5b = c
D. a + b + c = 12