A vessel contains a mixture of Grape, Pineapple and Banana juices in the respectively ratio of 4 : 6 : 5. 15 litres of this mixture is taken out and 8 litres of grape juice and 2 litres of pineapple juice is added to the vessel. If the resultant quantity of grape juice is 10 litres less than the resultant quantity of pineapple juice, what was the initial quantity of mixture in the vessel ? ( in litres)

A. 120 litres B. 150 litres C. 105 litres D. 135 litres Answer: Option D
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Solution(By Apex Team)

Let quantity of grape, pineapple and banana juice in the mixture be 4x, 6x and 5x respectively Total initial quantity of juice in the vessel = 4x + 6x + 5x = 15x litres In 15 litres of juice, Grape’s juice = 4 litres Pineapple’s juice = 6 litres Banana’s juice = 5 litres Resultant quantity of grape juice is 10 litres less than the resultant quantity of pineapple juice $\begin{array}{l}\Rightarrow(6x-6+2)-(4x-4+8)=10\\ \Rightarrow6x-4-4x-4=10\\ \Rightarrow2x-8=10\\ \Rightarrow2x=10+8\\ \Rightarrow x=9\\ \text{∴ Initial quantity of mixture}\\ \text{= 15x}\\ \text{= 15 × 9}\\ \text{= 135 litres}\end{array}$

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