Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average19 people went to a hotel for combine dinner party 13 by 8 runs. His new average is:

A. 20

B. 21

C. 28

D. 32

Show Answer

Answer-C Solution-

Solution(By Apex Team)

Let Ajit’s average be x for 9 innings. So, Ajit scored 9x run in 9 innings. In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x + 8) × 10 runs in 10 innings. Now, $\begin{array}{l} \Rightarrow 9 x+100=10 \times(x+8) \\ \text { or, } 9 x+100=10 x+80 \\ \text { or, } x=100-80 \\ \text { or, } x=20 \\ \text { New average }=(x+8) \\ =28 \text { runs } \end{array}$

Related Questions On Average


Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average19 people went to a hotel for combine dinner party 13 by 8 runs. His new average is:

A. 20
B. 21
C. 28
D. 32
Show Answer

Find the average of all the numbers between 6 and 34 which are divisible by 5.

A. 18
B. 20
C. 24
D. 30
Show Answer

In a family, the average age of a father and a mother is 35 years. The average age of the father, mother and their only son is 27 years. What is the age of the son?

A. 10 years
B. 10.5 years
C. 11 years
D. 12 years
Show Answer

If the arithmetic mean of 0, 5, 4, 3 is a, that of -1, 0, 1, 5, 4, 3 is b and that of 5, 4, 3 is c, then the relation between a, b, and c is.

A. a = b = c
B. a : b : c = 3 : 2 : 4
C. 4a = 5b = c
D. a + b + c = 12
Show Answer



More Related Questions On Average