### Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average19 people went to a hotel for combine dinner party 13 by 8 runs. His new average is:

**A.** 20

**B.** 21

**C.** 28

**D.** 32

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### Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average19 people went to a hotel for combine dinner party 13 by 8 runs. His new average is:

## Show Answer

### Answer-C
Solution-

__Solution(By Apex Team)__

Let Ajit’s average be x for 9 innings. So, Ajit scored 9x run in 9 innings.
In the 10th inning, he scored 100 runs then average became (x+8).
And he scored (x + 8) × 10 runs in 10 innings.
Now,
$\begin{array}{l} \Rightarrow 9 x+100=10 \times(x+8) \\ \text { or, } 9 x+100=10 x+80 \\ \text { or, } x=100-80 \\ \text { or, } x=20 \\ \text { New average }=(x+8) \\ =28 \text { runs } \end{array}$

Ajit has a certain average for 9 innings.

**A.** 20

**B.** 21

**C.** 28

**D.** 32