Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average19 people went to a hotel for combine dinner party 13 by 8 runs. His new average is:

A. 20

B. 21

C. 28

D. 32

Show Answer

Answer-C Solution-

Solution(By Apex Team)

Let Ajit’s average be x for 9 innings. So, Ajit scored 9x run in 9 innings. In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x + 8) × 10 runs in 10 innings. Now, $\begin{array}{l} \Rightarrow 9 x+100=10 \times(x+8) \\ \text { or, } 9 x+100=10 x+80 \\ \text { or, } x=100-80 \\ \text { or, } x=20 \\ \text { New average }=(x+8) \\ =28 \text { runs } \end{array}$

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