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An alloy contains zinc, copper and tin in the ratio 2 : 3 : 1 and another contains copper, tin and lead in the ratio 5 : 4 : 3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:

A. $\large\frac{1}{2} \mathrm{~kg}$ B. $\large\frac{1}{8} \mathrm{~kg}$ C. $\large\frac{3}{14} \mathrm{~kg}$ D. $\large\frac{7}{9} \mathrm{~kg}$ Answer: Option B
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Solution(By Apex Team)

Ratio of Zinc, Copper and Tin is given as, Z : C : T = 2 : 3 : 1. Now, let the first alloy be 12 kg (taken as 4 kg Zinc, 6 kg Copper and 2 Kg Lead). Weight of second alloy = 12 kg as, C : T : L = 5 : 4 : 3. (taken as 5 kg Copper, 4 kg Tin and 3 Kg Lead.) Alloys are mixed together to form third alloy. Then the ratio of content in it, Z : C : T : L = 4 : (6 + 5) : (2 + 4) : 3 Weight of third alloy = 12 + 12 = 24 Kg. So, weight of the Lead = $\Large\frac{3}{24}=\frac{1}{8}$ kg

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