# Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?

A. 2 times B. $2 \frac{1}{2} \text { times }$ C. $2 \frac{3}{4} \text { times }$ D. 3 times**Answer: Option A**

## Show Answer

Solution(By Apex Team)

Let Ronit’s present age be x yeras.
Then, Father’s present age
$\begin{array}{l}=(x+3x)\text{ years }\\
=4x\text{ years }\\
\therefore(4x+8)=\frac{5}{2}(x+8)\\
\Rightarrow8x+16=5x+40\\
\Rightarrow3x=24\\
\Rightarrow x=8\\
\text{Hence, required times}\\
\begin{array}{l}=\frac{4x+16}{x+16}\\
=\frac{48}{24}\\
=2\end{array}\end{array}$