If 7 times the seventh term of an Arithmetic Progression (AP) is equal to 11 times its eleventh term, then the 18th term of the AP will be

A. 0 B. 1 C. 2 D. -1 Answer: Option A
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Solution(By Apex Team)

Let the first term of the AP be a and the common difference = d 7th term = A7 = a + 6d 11th term = A11 = a + 10d According to question, $\begin{array}{l}\Rightarrow7\times(a+6d)=11\times(a+10d)\\ \Rightarrow7a+42d=11a+110d\\ \Rightarrow11a-7a=42d-110d\\ \Rightarrow4a=-68d\\ \Rightarrow a=-17d\\ \Rightarrow a+17d=0=A_{18}\end{array}$

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