### In the afternoon, a student read 100 pages at the rate of 60 pages per hour. In the evening, when she was tired, she read 100 more pages at the rate of 40 pages per hour. What was her average rate of reading the pages per hours ?

A. 60 B. 70 C. 48 D. 50 Answer: Option C
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### Solution(By Apex Team)

According to the question, Afternoon 100 pages read at the rate 60 pages per hour Total time taken to read 100 pages $\begin{array}{l}=\large\frac{100}{60}\\ =\large\frac{5}{3}\text{ hours }\\ \end{array}$
Evening 100 pages read at the rate 40 pages per hour Total time taken to read 100 pages $\begin{array}{l} =\large\frac{100}{40} \\ =\large\frac{5}{2} \text { hours } \end{array}$ Average rate of reading the pages per hour \begin{aligned}&=\frac{200}{\frac{5}{3}+\frac{5}{2}}\\ &=\frac{200\times6}{10+15}\\ &=\frac{200\times6}{25}\\ &=48\end{aligned}

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### If the arithmetic mean of 0, 5, 4, 3 is a, that of -1, 0, 1, 5, 4, 3 is b and that of 5, 4, 3 is c, then the relation between a, b, and c is.

A. a = b = c
B. a : b : c = 3 : 2 : 4
C. 4a = 5b = c
D. a + b + c = 12
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