# The angle of depression of a car, standing on the ground, from the top of a 75 m tower, is 30°. The distance of the car from the base of the tower (in metres) is.

A. $25 \sqrt{3}$ B. $50 \sqrt{3}$ C. $75 \sqrt{3}$ D. $150$**Answer: Option C**

## Show Answer

Solution(By Apex Team)

AB is a tower and AB = 75 m
From A, the angle of depression of a car C
on the ground is 30°
$\begin{array}{l}\text{Let distance BC}=x\\
\text{Now in right }\triangle\text{ACB},\\
\tan\theta=\frac{\text{AB}}{\text{BC}}\\
\Rightarrow\tan30^{\circ}=\frac{75}{x}\\
\Rightarrow\frac{1}{\sqrt{3}}=\frac{75}{x}\\
\Rightarrow x=75\sqrt{3}\text{m}\\
\therefore\text{BC}=75\sqrt{3}\text{m}\end{array}$