# The angle of depression of a point situated at a distance of 70m from the base of a tower is 60°. The height of the tower is-

A. $35 \sqrt{3} \mathrm{~m}$ B. $70 \sqrt{3} \mathrm{~m}$ C. $\frac{70 \sqrt{3}}{3} \mathrm{~ m}$ D. 70 m Answer: Option B
Let AB = Tower = h meter DAC = ACB = 60° BC = 70 meters $\begin{array}{l}\tan60^{\circ}=\frac{\text{AB}}{\text{BC }}\\ \Rightarrow\sqrt{3}\frac{\text{h}}{70}\\ \Rightarrow\text{h}=70\sqrt{3}\text{ meter }\end{array}$