### The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?

**A.** Rs. 5, Rs.7.50

**B.** Rs. 8, Rs. 12

**C.** Rs. 10, Rs. 16

**D.** Rs. 12, Rs. 14

## Show Answer

### Answer-C

Solution-

__Solution(By Apex Team)__

Total cost of 10 books = Rs. 120 Total cost of 8 books = Rs. 94 The cost of 2 books = Rs. 26 Let the price of each book be x and y. x + y = 26 – – – – – -(1) Given that the price of 1 book is 60% more than the other price $\begin{array}{l}\left(\frac{160}{100}\ right)y+y=26\\ \Rightarrow y\left(\frac{160}{100}+1\right)=26\\ \Rightarrow y\left(\frac{160+100}{100}\right )=26\\ \Rightarrow y=\frac{(26\times100)}{260}\\ \Rightarrow y=10\\ \text{ Substituting }y=10\text{ in (1) we get, }\ \ x+10=26\\ x=16\end{array}$