### The present age of a father is 3 years more than three times the age of his son. Three years hence, father’s age will be 10 years more than twice the age of the son. The father’s age is :

A. 33 years

B. 39 years

C. 45 years

D. 40 years

Let the present age of Son = x years And the father’s age = 3x + 3 $\begin{array}{l}\text{According to the question,}\\ \text{2 (x + 3) + 10 = 3x + 3 + 3}\\ \text{2x + 6 + 10 = 3x + 6}\\ \text{2x + 16 = 3x + 6}\\ \text{x = 10 years}\\ \text{Father’s age}\\ \text{= 3 × 10 + 3 = 33 years}\end{array}$