60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 : 2 and alloy B has tin and copper in the ratio 1 : 4, the amount of tin in the new alloy is –
A. 44 kg B. 53 kg C. 80 kg D. 24 kg Answer: Option AShow Answer
Solution(By Apex Team)
$\begin{aligned}&\text{Quantity of tin in 60 kg of A}\\
&=\left(60\times\frac{2}{5}\right)\mathrm{kg}\\
&=24\mathrm{~kg}\\
&\text{Quantity of tin in 100 kg of B}\\
&=\left(100 \times \frac{1}{5}\right) \mathrm{kg} \\
&=20 \mathrm{~kg}\end{aligned}$
∴ Quantity of tin in the new alloy
= (24 + 20) kg
= 44 kg
[oceanwp_library id=”4560″]
HI 
EN 