# An amount of Rs. 1,00,000 is invested in two types of shares. The first yields an interest of 9% p.a. and second, 11% p.a. If the total interest at the end of one year is $9 \frac{3}{4} \%$ then the amount invested in each share was?

A. Rs. 52, 500; Rs. 47, 500 B. Rs. 62, 500; Rs. 37, 500 C. Rs. 72, 500; Rs. 27, 500 D. Rs. 82, 500; Rs. 17, 500 Answer: Option B
Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (100000 – x). Then, $\begin{array}{l}=\left(\frac{x\times9\times1}{100}\right)+\left[\frac{(100000-x)\times11\times1}{100}\right]\\ =\left(100000\times\frac{39}{4}\times\frac{1}{100}\right)\\ \Leftrightarrow\frac{9x+1100000-11x}{100}=\frac{39000}{4}=9750\\ \Leftrightarrow2x=(1100000-975000)=125000\\ \Leftrightarrow x=62500\\ \therefore \text { Sum invested at } 9 \% \\ =\text { Rs. } 62500 \\ \text { Sum invested at } 11 \% \\ =\text { Rs. }(100000-62500) \\ =\text { Rs. } 37500 \end{array}$