# If the height of a vertical pole is $\sqrt{3}$ times the length of its shadow on the ground, then the angle of elevation of the sun at that time is

A. 30° B. 60° C. 45° D. 75° Answer: Option B
Let AB be a vertical pole and let its shadow be BC Let BC = x m, then length of pole $=\sqrt{3} x$ $\theta$ be the angle of elevation $\begin{array}{l} \therefore \tan \theta=\frac{A B}{B C}=\frac{\sqrt{3} x}{x}=\sqrt{3} \\ =\tan 60^{\circ} \\ \therefore \theta=60^{\circ} \end{array}$