The average of the first 100 positive integers is –

According to the question, As we know that average of ‘n’ positive integer is $\begin{array}{l}=\large\frac{n(n+1)}{2\times n}\\ =\large\frac{(n+1)}{2}\\ \text{ Here }\mathrm{n}=100\\ \therefore\large\frac{100+1}{2}\\ =\large\frac{101}{2}\\ =50.5\end{array}$