# The average of the first five multiples of 9 is:

A. 20

B. 27

C. 28

D. 30

### Solution(By Apex Team)

$\begin{array}{l}\text{Required average}\\ \begin{array}{l} =\Large\frac{\text { total sum of multiple of } 9}{5} \\ =\Large\frac{9+18+27+36+45}{5} \\ =27 \end{array}\end{array}$
Note that, average of 9 and 45 is also 27. And average of 18 and 36 is also 27.

## Related Questions On Average

A. 20
B. 21
C. 28
D. 32

A. 18
B. 20
C. 24
D. 30

A. 10 years
B. 10.5 years
C. 11 years
D. 12 years

### If the arithmetic mean of 0, 5, 4, 3 is a, that of -1, 0, 1, 5, 4, 3 is b and that of 5, 4, 3 is c, then the relation between a, b, and c is.

A. a = b = c
B. a : b : c = 3 : 2 : 4
C. 4a = 5b = c
D. a + b + c = 12