### What is the sum of the first 13 terms of an arithmetic progression if the first term is -10 and last term is 26?

A. 104 B. 140 C. 84 D. 98 Answer: Option A

### Solution(By Apex Team)

\begin{aligned}&S_n=\frac{n}{2}[a+l]\\ &S_{13}=\frac{13}{2}[-10+26]\\ &S_{13}=\frac{13}{2}[16]\\ &S_{13}=104\end{aligned}

A. 22
B. 25
C. 23
D. 24

A. 5
B. 6
C. 4
D. 3

A. -45
B. -55
C. -50
D. 0