I had Rs. 10000 with me. Out of this money I lent some money to A for 2 years 15% simple interest. I lent the remaining money to B for an equal number of years 18% simple interest. After 2 years, I found that A had given me Rs. 360 more as interest as compared to B. The amount of money which I had lent to B must have been.

A. Rs. 2000 B. Rs. 3000 C. Rs. 4000 D. Rs. 5000 Answer: Option C
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Solution(By Apex Team)

Let the sum lent to A be Rs. x. and that lent to B be Rs. (10000 – x) Then, $\begin{array}{l} \Rightarrow \frac{x \times 15 \times 2}{100}-\frac{(10000-x) \times 18 \times 12}{100}=360 \\ \Rightarrow 30 x-360000+36 x=36000 \\ \Rightarrow 66 x=396000 \\ \Rightarrow x=6000 \end{array}$ Hence, Sum lent to B = Rs. (10000 – 6000) = Rs. 4000