If the average of m numbers is n2 and that of n numbers is m2 , then the average of (m + n) numbers is.

A. m – n

B. mn

C. m + n

D. $\frac{\boldsymbol{m}}{\boldsymbol{n}}$

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Solution(By Apex Team)

$\begin{array}{l}\text{Sum of m numbers = mn}^2\\ \text{Sum of n numbers = nm}^2\\ \text{∴ Average of (m + n) numbers}\\ \begin{array}{l}=\Large\frac{mn(m+n)}{(m+n)}\\ =\mathrm{mn}\end{array}\end{array}$

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