Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi’s speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi’s speed is:
A. 12 km/h B. 10 km/h C. 8 km/h D. 6 km/h Answer: Option CShow Answer
Solution(By Apex Team)
Ajay → (x + 4) kmph.
A ________ 60 km _________ B
Ravi → x kmph.
Let the speed of Ravi be x kmph;
Hence, Ajay’s speed = (x + 4) kmph;
Distance covered by Ajay = 60 + 12 = 72 km;
Distance covered by Ravi = 60 – 12 = 48 km.
According to question,
$\begin{array}{l}\frac{72}{x+4}=\frac{48}{x}\\
\text{ or },\frac{3}{x+4}=\frac{2}{x}\\
\text{ or, }3x=2x+\\
\text{ or },x=8\mathrm{kmph}\end{array}$
