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Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi’s speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi’s speed is:

A. 12 km/h B. 10 km/h C. 8 km/h D. 6 km/h Answer: Option C
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Solution(By Apex Team)

Ajay → (x + 4) kmph. A ________ 60 km _________ B Ravi → x kmph. Let the speed of Ravi be x kmph; Hence, Ajay’s speed = (x + 4) kmph; Distance covered by Ajay = 60 + 12 = 72 km; Distance covered by Ravi = 60 – 12 = 48 km. According to question, $\begin{array}{l}\frac{72}{x+4}=\frac{48}{x}\\ \text{ or },\frac{3}{x+4}=\frac{2}{x}\\ \text{ or, }3x=2x+\\ \text{ or },x=8\mathrm{kmph}\end{array}$

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