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Running at 3/4 of his usual speed, an athlete improves his timing by 5 minutes. The time he usually takes to run the same distance is:

A. 15 min. B. 20 min. C. 25 min. D. 21 min. Answer: Option A
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Solution(By Apex Team)

Let us assume the usual speed of athlete be v units/minute, and usual time to be t minutes.
As, distance = speed × time
speed1 × time1 = speed2 × time2
Putting values we get,
So, v × t = (3v/4) × (t+5)
Or 4t = 3t + 15
Or t = 15 minutes
Hence, option (a) is correct.

माना कि समान्य गति (चाल) V इकाई/मिनट और समान्य समय t मिनट है।
चूंकि, दूरी = चाल1 × समय1 = चाल2 × समय2)
इसलिए, V × t = (3v/4) × (t + 5)
या 4t = 3t + 15
या t = 15 मिनट
 

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