### Ten years ago, the ages of the members of a joint family of eight people added up to 231 years. Three years later, one member died at the age of 60 years and a child was born during the same year. After another three years, one more member died, again at 60, and a child was born during the same year. The current average of this eight-member joint family is nearest to-

A. 21 years B. 22 years C. 23 years D. 24 years Answer: Option D
Show Answer

### Solution(By Apex Team)

Sum of the ages of 8 members, 10 years ago = 231 years Sum of the ages of all members, 7 years ago = (231 + 8 × 3 – 60) years = 195 years Sum of the ages of all members, 4 years ago = (195 + 8 × 3 – 60) years = 159 years Sum of the present ages of all 8 members = (159 + 8 × 4) years = 191 years ∴ Current average age = $\Large\frac{191}{8}$ years = 23.8 years ≈ 24 years

## Related Questions On Average

A. 20
B. 21
C. 28
D. 32
Show Answer

A. 18
B. 20
C. 24
D. 30
Show Answer

A. 10 years
B. 10.5 years
C. 11 years
D. 12 years
Show Answer

### If the arithmetic mean of 0, 5, 4, 3 is a, that of -1, 0, 1, 5, 4, 3 is b and that of 5, 4, 3 is c, then the relation between a, b, and c is.

A. a = b = c
B. a : b : c = 3 : 2 : 4
C. 4a = 5b = c
D. a + b + c = 12
Show Answer