### The 3rd and 8th term of an arithmetic progression are -13 and 2 respectively. What is the 14th term?

A. 23 B. 17 C. 20 D. 26 Answer: Option C

### Solution(By Apex Team)

Let the first term of an AP = a and the common difference = d 3rd term of AP = A3 = a + 2d = -13 …… (1) 8th term = A8 = a + 7d = 2 …… (2) Subtracting equation (1) from (2), we get : ⇒ 7d – 2d = 2 – (-13) ⇒ 5d = 15 ⇒ d = $\Large\frac{15}{5}$ = 3 Substituting it in equation (2) ⇒ a = 2 – 7(3) = 2 – 21 = -19 ∴ 14th term = A14 = a + 13d = -19 + 13(3) = -19 + 39 = 20

A. 22
B. 25
C. 23
D. 24

A. 5
B. 6
C. 4
D. 3

A. -45
B. -55
C. -50
D. 0