### The acid and water in two vessels A and B are in the ratio 4 : 3 and 2 : 3. In what ratio should the liquid in both the vessels be mixed to obtain a new mixture in vessel C containing half acid and half water ?

A. 7 : 5 B. 5 : 7 C. 7 : 3 D. 5 : 3 Answer: Option A

### Solution(By Apex Team)

$\begin{array}{l}\text{According to the question,}\\ \begin{array}{ccc}&\text{ Acid }&&\text{ Water }\\ \text{ Vessel A }&4&:&3\\ \text{ Vessel B }&2&:&3\end{array}\end{array}$ By alligation method –
So, Required ratio = 7 : 5

## Related Questions On Alligation

A. 2 : 5
B. 3 : 5
C. 5 : 3
D. 5 : 2

### An alloy contains zinc, copper and tin in the ratio 2 : 3 : 1 and another contains copper, tin and lead in the ratio 5 : 4 : 3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:

A. $\large\frac{1}{2} \mathrm{~kg}$
B. $\large\frac{1}{8} \mathrm{~kg}$
C. $\large\frac{3}{14} \mathrm{~kg}$
D. $\large\frac{7}{9} \mathrm{~kg}$

A. 81 litres
B. 71 litres
C. 56 litres
D. 50 litres