### The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly added. The first is 18 greater than the actual number and the second number added is 13 instead of 33. Find the correct average.

A. 40.2

B. 40.4

C. 40.6

D. 40.8

$\begin{array}{l}\text{Correct sum}\\ \text{= (40.2 × 10 – 18 + 33 – 13)}\\ \text{= 404}\\ \text{∴ Correct average}\\ =\left(\Large\frac{404}{10}\right)\\ =40.4\end{array}$