### The average of 5 consecutive integers starting with ‘m’ is n. What is the average of 6 consecutive integers starting with (m + 2)?

A. $\Large\frac{(2 n+5)}{2}$ B. (2n + 2) C. (n + 3) D. $\Large\frac{(2 n+9)}{2}$ Answer: Option A

### Solution(By Apex Team)

According to the question, Let M = 1 ∴ 5 consecutive integers are = 1, 2, 3, 4, 5 $\begin{array}{l}\therefore\frac{1+2+3+4+5}{5}=n\\ n=\frac{15}{5}\\ =3\end{array}$ ∴ 6 consecutive integers starting with (m + 2) are = 3, 4, 5, 6, 7, 8 $\begin{array}{l}\therefore\Large\frac{3+4+5+6+7+8}{6}\\ =\Large\frac{33}{6}\\ =\Large\frac{11}{2}\end{array}$ Now check from option to put n = 3 $\begin{array}{l}\text{Option : (A) }\\ \Large\frac{(2n+5)}{2}\\ =\Large\frac{2\times3+5}{2}\\ =\frac{11}{2}\ \left(\text{satisfied}\right)\end{array}$

A. 20
B. 21
C. 28
D. 32

A. 18
B. 20
C. 24
D. 30

A. 10 years
B. 10.5 years
C. 11 years
D. 12 years