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**The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. The average of the remaining two numbers is :**

A. 4.6
B. 4.8
C. 4.5
D. 4.7
**Answer: Option A**

## Show Answer

Solution(By Apex Team)

Let the six number be a, b, c, d, e, f According to the question, $\begin{array}{l}\Rightarrow\frac{a+b+c+d+e+f}{6}=3.95\\ \Rightarrow a+b+c+d+e+f=23.7\ldots(i)\\ \frac{a+b}{2}=3.4\\ \Rightarrow a+b=6.8\ldots..\text{ (ii) }\\ \frac{c+d}{2}=3.85\\ \Rightarrow\mathrm{c}+\mathrm{d}=7.7\ldots.\left(iii\right)\end{array}$ Put the value of equation (ii) and equation (iii) in equation (i) $\begin{array}{l}e+f=23.7-7.7-6.8\\ e+f=9.2\\ \therefore\text{ Average }=\frac{9.2}{2}\\ =4.6\end{array}$