### The average of the first five multiples of 9 is:

**A.** 20

**B.** 27

**C.** 28

**D.** 30

## Show Answer

### Answer-B

Solution-

__Solution(By Apex Team)__

$\begin{array}{l}\text{Required average}\\ \begin{array}{l} =\Large\frac{\text { total sum of multiple of } 9}{5} \\ =\Large\frac{9+18+27+36+45}{5} \\ =27 \end{array}\end{array}$

Note that, average of 9 and 45 is also 27. And average of 18 and 36 is also 27.

Note that, average of 9 and 45 is also 27. And average of 18 and 36 is also 27.

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