### The average of the first five multiples of 9 is:

A. 20

B. 27

C. 28

D. 30

$\begin{array}{l}\text{Required average}\\ \begin{array}{l} =\Large\frac{\text { total sum of multiple of } 9}{5} \\ =\Large\frac{9+18+27+36+45}{5} \\ =27 \end{array}\end{array}$