The average of the squares of first ten natural numbers is.
A. 35.5 B. 36 C. 37.5 D. 38.5 Answer: Option DShow Answer
Solution(By Apex Team)
As we know that average of square of “n” natural number is
$\begin{array}{l}=\Large\frac{n(n+1)(2n+1)}{6n}\\
=\Large\frac{(n+1)(2n+1)}{6}\end{array}$
According to the question,
Average of square of first ten natural number is
$\begin{array}{l}=\Large\frac{(10+1)(20+1)}{6}\\
=\Large\frac{11\times21}{6}\\
=38.5\end{array}$
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