### The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?

**A.** Rs. 5, Rs.7.50

**B.** Rs. 8, Rs. 12

**C.** Rs. 10, Rs. 16

**D.** Rs. 12, Rs. 14

## Show Answer

### Answer-C

Solution-

__Solution(By Apex Team)__

Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 – – – – – -(1)
Given that the price of 1 book is 60% more than the other price
$\begin{array}{l}\left(\frac{160}{100}\right)y+y=26\\
\Rightarrow y\left(\frac{160}{100}+1\right)=26\\
\Rightarrow y\left(\frac{160+100}{100}\right)=26\\
\Rightarrow y=\frac{(26\times100)}{260}\\
\Rightarrow y=10\\
\text{ Substituting }y=10\text{ in (1) we get, }\\
x+10=26\\
x=16\end{array}$