###
**The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
**

A. Rs. 5, Rs.7.50
B. Rs. 8, Rs. 12
C. Rs. 16, Rs. 10
D. Rs. 12, Rs. 14

A. Rs. 5, Rs.7.50 B. Rs. 8, Rs. 12 C. Rs. 16, Rs. 10 D. Rs. 12, Rs. 14

## Show Answer

### Answer-C Solution-

__Solution(By Apex Team)__

Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 – – – – – – (1)
$\left(\Large\frac{160}{100}\right) x+y=26$
On Solving for y, we get
y = 10
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16
So the price of each book is Rs. 16 and Rs. 10 respectively.
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