### The average weight of A, B and C is 40 kgs. Weight of C is 24 kgs more than A’s weight and 3 kgs less than B’s weight. What will be the average weight of A, B, C and D, if D weights 15 kgs less than C?

A. 25.2°C B. 25.5°C C. 25.6°C D. 25°C Answer: Option D
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### Solution(By Apex Team)

Average weight of A, B and C = 40 kgs Total weights of A , B and C = 40 × 3 = 120 kgs Weight of C = (A + 24) and C = (B – 3) ∴ A + 24 = B – 3 ⇒ B = A + 27 Now A + B + C = 120 ⇒ A + A + 27 + A + 24 = 120 ⇒ 3A + 51 = 120 ⇒ A = $\large\frac{69}{3}$ = 23 kg B = A + 27 = 23 + 27 = 50 kg C = 120 – 23 – 50 = 47 kg D = 47 – 15 = 32 kg ∴ Required average weight of A, B, C and D $\begin{array}{l} =\Large\frac{23+50+47+32}{4} \\ =\Large\frac{152}{4} \\ =38 \mathrm{~kg} \end{array}$

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### If the arithmetic mean of 0, 5, 4, 3 is a, that of -1, 0, 1, 5, 4, 3 is b and that of 5, 4, 3 is c, then the relation between a, b, and c is.

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