###
**The average weight of A, B and C is 40 kgs. Weight of C is 24 kgs more than A’s weight and 3 kgs less than B’s weight. What will be the average weight of A, B, C and D, if D weights 15 kgs less than C?
**

A. 25.2°C
B. 25.5°C
C. 25.6°C
D. 25°C
**Answer: Option D**

## Show Answer

Solution(By Apex Team)

Average weight of A, B and C = 40 kgs
Total weights of A , B and C
= 40 × 3 = 120 kgs
Weight of C = (A + 24) and C = (B – 3)
∴ A + 24 = B – 3
⇒ B = A + 27
Now A + B + C = 120
⇒ A + A + 27 + A + 24 = 120
⇒ 3A + 51 = 120
⇒ A = $\large\frac{69}{3}$ = 23 kg
B = A + 27 = 23 + 27 = 50 kg
C = 120 – 23 – 50 = 47 kg
D = 47 – 15 = 32 kg
∴ Required average weight of A, B, C and D
$\begin{array}{l}
=\Large\frac{23+50+47+32}{4} \\
=\Large\frac{152}{4} \\
=38 \mathrm{~kg}
\end{array}$

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