The length of shadow of a tower on the plane ground is $\sqrt{3}$ times the height of the tower. The angle of elevation of sun is.

A. 45° B. 30° C. 60° D. 90° Answer: Option B
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Solution(By Apex Team)

Let AB be tower and BC be its shadow ∴ Let AB = x Length of shadow Height and Distance. image $\begin{array}{l}\text{Then BC}=\sqrt{3}\times x\\ =\sqrt{3}x\\ \begin{aligned}\therefore\tan\theta&=\frac{AB}{BC}\\ &=\frac{x}{\sqrt{3}x}\\ &=\frac{1}{\sqrt{3}}\\ &=\tan30^{\circ}\\ \therefore\theta=30^{\circ}&\\ &\end{aligned}\end{array}$ ∴ Angle of elevation of the sun = 30∘