ssccglapex

Two A.P.’s have the same common difference. The first term of one of these is 8 and that of the other is 3. The difference between their 30th terms is

A. 11 B. 3 C. 8 D. 5 Answer: Option D
Show Answer

Solution(By Apex Team)

In two A.P.’s common-difference is same Let A and a are two A.P. ’s First term of A is 8 and first term of a is 3 $\begin{array}{l} A_{30}-a_{30}=8+(30-1) d-3-(30-1) d \\ =5+29 d-29 d \\ =5 \end{array}$

Related Questions On Progressions


How many terms are there in 20, 25, 30 . . . . . . 140?

A. 22
B. 25
C. 23
D. 24
Show Answer

Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.

A. 5
B. 6
C. 4
D. 3
Show Answer

Find the 15th term of the sequence 20, 15, 10 . . .

A. -45
B. -55
C. -50
D. 0
Show Answer

The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is

A. 600
B. 765
C. 640
D. 680
Show Answer



More Related Questions On Progressions